16^2^x+^1=128

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Solution for 16^2^x+^1=128 equation: 



16^2^x+^1=128

We move all terms to the left:

16^2^x+^1-(128)=0

determiningTheFunctionDomain
16^2^x-128+^1=0

We add all the numbers together, and all the variables

16^2^x=0

x=0/1

x=0

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